4[3+c]+c=c+4

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Solution for 4[3+c]+c=c+4 equation:


Simplifying
4[3 + c] + c = c + 4
[3 * 4 + c * 4] + c = c + 4
[12 + 4c] + c = c + 4

Combine like terms: 4c + c = 5c
12 + 5c = c + 4

Reorder the terms:
12 + 5c = 4 + c

Solving
12 + 5c = 4 + c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1c' to each side of the equation.
12 + 5c + -1c = 4 + c + -1c

Combine like terms: 5c + -1c = 4c
12 + 4c = 4 + c + -1c

Combine like terms: c + -1c = 0
12 + 4c = 4 + 0
12 + 4c = 4

Add '-12' to each side of the equation.
12 + -12 + 4c = 4 + -12

Combine like terms: 12 + -12 = 0
0 + 4c = 4 + -12
4c = 4 + -12

Combine like terms: 4 + -12 = -8
4c = -8

Divide each side by '4'.
c = -2

Simplifying
c = -2

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